Lesson plan

Inversion temperature

The inversion temperature in thermodynamics and cryogenics is the critical temperature below which a gas that is expanding at constant enthalpy will experience a temperature decrease, and above which will experience a temperature increase. This temperature change is known as the Joule–Thomson effect, and is exploited in the liquefaction of gases. Inversion temperature depends on the nature of the gas. The temperature of an ideal gas remains constant during expansion. For a van der Waals gas we can calculate the enthalpy H using statistical mechanics as : H = \frac{5}{2} N k_\mathrm B T + \frac{N^2}{V} (b k_\mathrm B T - 2a) where N is the number of molecules, V is volume, T is temperature (in the Kelvin scale), k_\mathrm B is the Boltzmann constant, and a and b are constants depending on intermolecular forces and molecular volume, respectively. From this equation, if enthalpy is kept constant and there is an increase of volume, temperature must change depending on the sign of b k_\mathrm B T - 2a . Therefore, our inversion temperature is given where the sign flips at zero, or : T_\text{inv} = \frac{2a}{b k_\mathrm B} = \frac{27}{4} T_\mathrm c , where T_\mathrm c is the critical temperature of the substance.…

Back to article

Article summary

The inversion temperature in thermodynamics and cryogenics is the critical temperature below which a gas that is expanding at constant enthalpy will experience a temperature decrease, and above which will experience a temperature increase. This temperature change is known as the Joule–Thomson effect, and is exploited in the liquefaction of gases. Inversion temperature depends on the nature of the gas. The temperature of an ideal gas remains constant during expansion. For a van der Waals gas we can calculate the enthalpy H using statistical mechanics as : H = \frac{5}{2} N k_\mathrm B T + \frac{N^2}{V} (b k_\mathrm B T - 2a) where N is the number of molecules, V is volume, T is temperature (in the Kelvin scale), k_\mathrm B is the Boltzmann constant, and a and b are constants depending on intermolecular forces and molecular volume, respectively. From this equation, if enthalpy is kept constant and there is an increase of volume, temperature must change depending on the sign of b k_\mathrm B T - 2a . Therefore, our inversion temperature is given where the sign flips at zero, or : T_\text{inv} = \frac{2a}{b k_\mathrm B} = \frac{27}{4} T_\mathrm c , where T_\mathrm c is the critical temperature of the substance.…

Key claims

No claims recorded.

Discussion questions

  1. Summarise the article in your own words. Which single claim would you verify first, and why?
  2. Which claim in this article is most likely to be revised as the sources update? How would you check its current status?
  3. If two sources disagreed about one of these facts, what would you need in order to trust one over the other?

Bibliography

No sources recorded.

Key claims and bibliography are generated from the same tracked claims and sources as the article page.